sum of 1 2 2 3 3 4 n n 1

Question

Write a program to compute 1/2+2/3+3/4+...+n/n+1 with a given n input by console (n>0).

Example: If the following n is given as input to the program: 5

Then, the output of the program should be: 3.55

Answer 1

num = int(input("Enter a number: "))
newnum = 0

for each in range(1,num+1):
    newnum = newnum+(each/(each+1))

print("computed value : ",format(round(newnum,2)))

Comments

Nisha,

Can You please explain, how it works ?

how come 3.55 is coming up ?

Please

Komal S Patel

+447534288877

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Hey, @Komal,

While executing this code I am getting the exact output that is required. If you are facing any error please post that.

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This prog. is right and in last format you can write and not that doesn't make any change.

Answer 2

n=int(input("Enter the number of terms: "))

sum=0

for i in range(1,n+1):
    sum=sum+(i/(i+1))

print("The sum of series is: ",round(sum,2))

Answer 3

n = int(input("Enter the number:- "))
i = 1
ans1 = 0
while i <= n:
    # print(i, n)
    ans1 = ans1 + (i / (i + 1))
    i = i + 1

print(round(ans1, 2))