Python error IndentationError expected an indented block

Question

I am trying to execute the following python code:

def example(p,q):

a = p.find(" ")
b = q.find(" ")
str_p = p[0:a]
str_q = p[b+1:]

if str_p == str_q:
    result = True
else:
    result = False
return result

And I get the folloeing error:

IndentationError: expected an indented block

Comments

Python error  IndentationError  expected an indented block  | Edureka Community
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Answer 1

Python requires its code to be indented and spaced properly. Never mix tabs and spaces. If you're using tabs stick to tabs and if you're using space stick to space.

Also in your code, change this part:

if str_p == str_q:
    result = True
else:
    result = False
return result

To

return str_p == str_q

Hope it helps!!

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Thanks!

Comments

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voices= engine.getProperty('voices')
print(voices[1].id)
engine.setProperty('voice', voice[1].id)

def speak(audio):
    engine.say(audio)
    engine.runAndWait()

    if __name__=="__main__" :

speak("Code With Harry")

---

Hey, @There,

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Answer 2

Putting in an extra space or leaving one out where it is needed will surely generate an error message . Some common causes of this error include:

•     Forgetting to indent the statements within a compound statement
•     Forgetting to indent the statements of a user-defined function.

The error message IndentationError: expected an indented block would seem to indicate that you have an indentation error. It is probably caused by a mix of tabs and spaces. The indentation can be any consistent white space . It is recommended to use 4 spaces for indentation in Python, tabulation or a different number of spaces may work, but it is also known to cause trouble at times. Tabs are a bad idea because they may create different amount if spacing in different editors . 

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Comments

Thank you for your simple explanation!!

Answer 3

IndentationError:  what is the mean

Comments

Hello,

For your query you can refer this:https://www.edureka.co/community/80421/indentationerror-expected-an-indented-block

Hope it helps you!!

Thank You!!

---

Hi, @There,

Whenever you have a situation with code inside of a statement (such as the code that defines the main() function), that 'inside' code must be indented, and must be indented consistently. If you forget to indent, you'll see this error.

Answer 4

In python, indentation indicates the block of code for control flow statements, class, and function definitions. The other programming languages, such as C#, JAVA, C/C++, will use braces { } to define a block of code. So, while writing the code in python, you need to follow the indentation. Please check the following resource to know about indentation importance in python.

How do i resolve the unexpected indent error in python?

Answer 5

Hi Rhea,

As everyone else has mentioned, python identifies a new block of code based on indentations. 

In this case your, all the lines under your function should be indented. Then only Python can understand that these lines are the body of the function.

Try modifying your code like this:

def example(p,q):

    a = p.find(" ")
    b = q.find(" ")
    str_p = p[0:a]
    str_q = p[b+1:]

    if str_p == str_q:
        result = True
    else:
        result = False
    return result

Hope this helps.

Answer 6

Before if and else there should be 2 spaces.

Answer 7

IndentationError: expected an indented block

The above error means you did some space error in your code or program.

Answer 8

class Formula():
    def interest(self, P, N, R):
        self.money=P*N*R/100
        return self.money
class Tamil(Formula):
    def c1(self):
    class_name=customer1.__class__.__name__
    print(f"Enter the Details of {class_name}:")
    P=float(input("Enter the principal amount:"))
    N=int(input("Enter the number of years:"))
    R=float(input("Enter the rate of interest:"))
    self.amount = Mainkey.interest(P, N, R)
    print(f"{class_name} will be receiving Rupees {self.money} as interest.")
    print("**************")
    
class Madhu(Formula):
    def c2(self):
    class_name=customer1.__class__.__name__
    print(f"Enter the Details of {class_name}:")
    P=float(input("Enter the principal amount:"))
    N=int(input("Enter the number of years:"))
    R=float(input("Enter the rate of interest:"))
    self.amount = Mainkey.interest(P, N, R)
    print(f"{class_name} will be receiving Rupees {self.money} as interest.")
    print("**************")
    
class Sathiya(Formula):
    def c3(self):
    class_name=customer1.__class__.__name__
    print(f"Enter the Details of {class_name}:")
    P=float(input("Enter the principal amount:"))
    N=int(input("Enter the number of years:"))
    R=float(input("Enter the rate of interest:"))
    self.amount = Mainkey.interest(P, N, R)
    print(f"{class_name} will be receiving Rupees {money} as interest.")
    print("**************")
        
mainkey=Formula()
customer1=Tamil()
customer2=Madhu()
customer3=Sathiya()

customer1.c1()
customer2.c2()
customer3.c3()

Answer 9

File "main.py", line 11

Exit

Width(x)

IndentationError: expected an indented b lock after 'for' statement on line 10