It is part of a series.
Replace pow() with the previous iteration's value.
There is no need for code to call pow ().
Pow(x, 5 * I - 1) and pow(-1, I - 1) may be formed since both have an int exponent dependent on the iterator I from the previous loop iteration.
Example:
Let f(x, i) = pow(x, 5 * i ...READ MORE
Jun 21, 2022
in C++
by
Damon
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