Solve the quadratic equation using lambda functions in Python

Question

I want to convert this code, which is to solve the quadratic equation, into a lambda function

from math import sqrt
def Equation(a,b,c):
    r = b ** 2 - 4 * a * c
    if r > 0:
        num_roots = 2
        x1 = (((-b) + sqrt(r)) / (2 * a))
        x2 = (((-b) - sqrt(r)) / (2 * a))
        print("There are 2 roots: %f and %f" % (x1, x2))
    elif r == 0:
        num_roots = 1
        x = (-b) / 2 * a
        print("There is one root: ", x)
    else:
        num_roots = 0
        print("No roots, discriminant < 0.")

Equation(1,2,0)

Answer 1

Hello @ Ø§Ù…یرحمزه ,

from math import sqrt

Root = lambda a, b, c: ((-b + sqrt((b * b) - (4 * a * c))) / (2 * a), (-b - sqrt((b * b) - (4 * a * c))) / (2 * a))

print(Root(1,2,0))      # call the lambda function

Hope it helps!!
Thank You!!