Replace every character of string by character whose ASCII value is K times more than it

Question

Secret Message

Description

You write all your passwords in a diary so that you don't forget them. But clearly this is too risky, so you came up with a simple plan, you will simply write it by shifting all the alphabets by a certain step. For eg: if you decide your step to be 3, then 'a' will become 'd', and 'k' will become 'n' and so for all alphabets. The last alphabets will simply circle back to 'a'. In this case, 'y' will become 'b' and so on. Now you just have to remember the step size, can then you can check the password anytime you want. You decided to write code to do this, now that you have learned coding in python. Your code will take in the step size and what is written in the diary and give out the real password.

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Input:
A list of two elements.
The first element will be a string consisting of only alphabets which is taken from the diary and the second element will be the step size.

Output:
A string denoting the password

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Sample input:
['ytKveh' 4]

Sample output:
upGrad

Explanation:
The password was 'upGrad'. Upon changing it by step of 4,
u became y,
p became t,
G became K,
r became v,
a became e,
d became h,
and thus what was written in the diary was ytKveh 

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Sample input:
['banana', 7]

Sample output:
utgtgt

Execution time limit

Default.

Comments

import ast
mylist=ast.literal_eval(input())
stringMessage=mylist[0]
shift_value=mylist[1]
#start writing your code from here
def shift_string(message, n):
    list1=[]
    for i in message:
        ch = i
        base = ord('a' if ch.islower() else 'A')
        x = chr((ord(ch) - base - n) % 26 + base)
        list1.append(x)
    return("".join(list1))
print(shift_string(stringMessage,shift_value))

Answer 1

Hi @Vaibhav! In such a case what you can do is, 

ask the user for the password(which will be in the string format)

take each letter of the string and convert it into a character and use the ord() which will return its Unicode.

To this Unicode, you can add the count value and convert it back to a string.

Finally, print it'

You can use the following code:

password = input("Enter the password")
count = input("Enter the count")
final_pass = ""
for x in list(password):
    y = chr(ord(x) + count)
    final_pass = final_pass + y
print(final_pass)

Comments

it does't works for i/p banana and 7

---

This will give issue when the last alphabet is Z and the requirement is to have only alphabets in the output.

Answer 2

Refer below code for your problem statement

def swap_letters(word, step_count):
    final_word = ""
    for x in list(word):
#         for lowercase letters crossing the Ascii values
        if(ord(x)-step_count<97 and ord(x)>96):
            w = 123-abs(97-(ord(x)-step_count))
            y = chr(w)
            final_word = final_word + y
            
#           for uppercase letters crossing the Ascii values
        elif(ord(x)-step_count<65 and ord(x)<91):
            w = 91-abs(65-(ord(x)-step_count))
            y = chr(w)
            final_word = final_word + y
            
#           for normal letters within the Std Ascii Values
        else:
            y = chr(ord(x)-step_count)
            final_word = final_word + y
    return final_word
    
swap_letters(input(),int(input()))