Refer the following piece of code:
e1=datetime.timedelta(days=32, seconds=0, microseconds=0, milliseconds=0, minutes=0, hours=4, weeks=8)
e2=datetime.timedelta(days=5, seconds=0, microseconds=0, milliseconds=0, minutes=0, hours=4, weeks=8)
e3=e1-e2
e4=e3//3
print(e4)
OUTPUT:
9 days, 0:00:00