How to extract file base name without path and extension in bash

0 votes

So, I've a few file names like these:

/the/path/foo.txt
bar.txt

I hope to be getting:

foo
bar

I'm trying to do this;

#!/bin/bash

fullfile=$1
fname=$(basename $fullfile)
fbname=${fname%.*}
echo $fbname

But it doesn't work. Can anyone help me?

May 31, 2019 in Linux Administration by Upasana
• 8,620 points
5,916 views

1 answer to this question.

0 votes

You don't actually have to call the external basename command. You could use the following commands,instead:

$ s=/the/path/foo.txt
$ echo ${s##*/}
foo.txt
$ s=${s##*/}
$ echo ${s%.txt}
foo
$ echo ${s%.*}
foo

Note: This solution worksin all recent (post 2004POSIX compliant shells, (e.g. bash, dash, ksh, etc.).

answered May 31, 2019 by Shubham
• 13,490 points

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