Selenium Exception error -Element is not clickable at point x y Other element would receive the click

Question

I am adding a customer in a billing software through selenium web driver,but after providing all the details, It is not performing click operation over the add button and showing the error -  

"Exception in thread "main" org.openqa.selenium.ElementClickInterceptedException: element click intercepted: Element <button type="button" class="btn  btn-info btn-sm" name="btnAddCust" id="btnAddCust" data-toggle="modal" data-target="#CustModal" title="Add Customer">...</button> is not clickable at point (317, 377). Other element would receive the click: <input type="text" name="birthDate" class="form-control pull-right" id="birthDate" data-mask=""> "

I am using the code  - 

Thread.sleep(1000);
        //driver.findElement(By.xpath("//*[@id=\"btnAddCust\"]")).click();
        WebElement el = driver.findElement(By.id("btnAddCust"));
        el.click();

Answer 1

Hi Kumar, you can use implicit_wait() method to let the driver identify elements properly. Or, you can also use relative_xpath to locate the element. You can get the button by xpath using ChroPath.

Answer 2

If waitings for element, sleeps and oher stuffs like this are not working, try to click using JS, because probably something is overlaying this element.
Something like this:

WebElement element = driver.findElement(By.xpath(“xpath”));
JavascriptExecutor executor = (JavascriptExecutor)driver;
executor.executeScript(“arguments[0].click();”, element);

For details, You can even check out Selenium concepts with the Selenium online training.

Comments

Hi Kim, I want to select the element with text 'Sewa' from ui menu using vba, please help. thanks

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If you have 2 or 10 menu's on your page as is the case with you,then you would have to separate them with different classes.

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Thanks. That worked.

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Thanks Douglas

Answer 3

WebElement element = driver.findElement(By.xpath(“xpath”));
JavascriptExecutor executor = (JavascriptExecutor)driver;
executor.executeScript(“arguments[0].click();”, element);

or 

WebElement element = driver.findElement(By("element_path"));
Actions actions = new Actions(driver);
actions.moveToElement(element).click().perform();

Answer 4

Two things can go wrong in this scenario:

1. The button is not found (and thus you would have NullPointerException on method click()) so it will break before with NoSuchElementException.
2. The button is not clickable (for some reasons) - and then you will have ElementNotClickableException.

I'm not logging each step. I'm logging Exceptions on Framework level + doing screenshots on Exception or failing assertion).

So you are safe with removing it and not gaining much (you wouldn't analyze 10000 lines of logs to check if something was logged).