Python program to print occurrence of character in string

Question

I am trying to write a program which counts and print the numbers of each character in a string input by the console.

Example: If the following string is given as input to the program:

abcdefgabc

Then, the output of the program should be:

a,2

c,2

b,2

e,1

d,1

g,1

f,1

Please provide the code for this

Comments

How would you get this code to print as in 'There are x uppercase, Y lowercase and Z numbers in this string'?

Answer 1

Try this:

string=input("Enter the string !!")

newstr=list(string)

newlist=[]

for j in newstr:

    if j not in newlist:

        newlist.append(j)

        count=0

        for i in range(len(newstr)):

            if j==newstr[i]:

                count+=1

        print("{},{}".format(j,count))

Hope it helps!!

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Thanks!

Answer 2

Try the below code

inputString = input("Enter a string: ").casefold()

#casefold() is to ensure that uppercase and lower case charachter is treated same.
#If you don't want, you can remove casefold()

tempStr = ''
for char in inputString:
    if char not in tempStr:
        print(char, ', ', inputString.count(char))
        tempStr = tempStr+char

Comments

thank you too so much .. after searching all the day finally i got it .. thanks again

---

How would you get this code to print as in 'There are x uppercase, Y lowercase and Z numbers in this string'?

Answer 3

Try below code

string = input("Enter a string: ")
lst1 = []
for char in string:
    if char not in lst1:
        lst1.append(char)
for item in lst1:
    print(item,string.count(item), sep = ",")

Answer 4

Consider a list of characters (characters may be alphabets, special characters, digits). Write a Python program to do the following:  

1) Count total number of elements in the list  

2) Count total number of vowels in the list (vowels are ‘a’, ‘e’, ‘i’, ‘o’, ‘u’) 

3) Count total number of consonants in the list (a consonant is an alphabet other than vowel)  

4) Count total number of characters other than vowels and consonants  

Display all the values with appropriate titles.  

listChar = ['$','a','8','!','9','i','a','y','u','g','q','l','f','b','t']

c = 0

cVowel = 0

cConst = 0

cOther = 0

for i in listChar :

    c += 1

    if i in 'aeiou' :

        cVowel = cVowel + 1

    elif i in '!@#$%^&*()+-*/123456789~`' :

        cOther = cOther + 1

    else :

        cConst = cConst + 1

print ("total number of element in the list  : ", c)

print("count vowels characters : ",cVowel)

print("count consonants characters : ",cConst)

print("count other characters : ",cOther)

Answer 5

Write a Python program to take input of a string from the user and then create a dictionary  containing each character of the string along with their frequencies. (e.g. if the string is ‘banana’  then output should be {'b': 1, 'a': 3, 'n': 2}.

d = dict()

user = input ("enter a string ::-- ")

lst = list(user)

l = len(lst)

for i in range(l) :

    c = 0

    for j in range(l) :

        if lst[i] == lst[j ]:

            c += 1

    d[lst[i]] = c

print("dictionary is  :: ",d)

Answer 6

str3 = 'abcdefgabc'
final_lst = []
for char in str3:
    if char not in final_lst:
        final_lst.extend([char,str3.count(char)])

it = iter(final_lst)
for x in it:
    print(x, next(it), sep = ",")

Answer 7

n=input()
l={}
for x in n:
    if x  in l:
        l[x]=l[x]+1
    else:
        l[x]=1
for z,m in l.items():
    print("{}{}".format(z,m),end="")

Answer 8

Try it:

str=input('Enter a string:')
str1=set(str)
str1=list(sorted(str1))
for i in range(len(str1)):
    x=str.count(str1[i])
    print(str1[i],x)