I need code to count syllables in words like hairy having two syllables My code works but fails for HAIRY which has only one syllable

Question

def syllable_count(word):
    count = 0
    vowels = "aeiouy"
    if word[0] in vowels:
        count += 1
    for index in range(1, len(word)):
        if word[index] in vowels and word[index - 1] not in vowels:
            count += 1
            if word.endswith("e"):
                count -= 1
    if count == 0:
        count += 1
    return count

TEST

print(syllable_count("HAIRY"))

Expected: 2

Received: 1