Based on your example, supposing id2 always exist, you can aggregate rows, group by id2:
select max(id1) id1, id2, max(id3) id3 from
( --your dataset as in example
select 'A' as id1, 1 as id2, null as id3 union all
select null as id1, 1 as id2, 'Alpha' as id3 union all
select null as id1, 2 as id2, 'Beta' as id3 union all
select 'A' as id1, 2 as id2, null as id3
)s
group by id2;
OK
A 1 Alpha
A 2 Beta
Time taken: 58.739 seconds, Fetched: 2 row(s)
And now I'm trying to implement your logic as you described:
select --pass2
id1, id2, id3,
case when lag(id2) over (order by id2, GroupId) = id2 then lag(GroupId) over (order by id2, GroupId) else GroupId end GroupId2
from
(
select --pass1
id1, id2, id3,
case when
lag(id1) over(order by id1, NVL(ID1,ID3)) =id1 then lag(NVL(ID1,ID3)) over(order by id1, NVL(ID1,ID3)) else NVL(ID1,ID3) end GroupId
from
( --your dataset as in example
select 'A' as id1, 1 as id2, null as id3 union all
select null as id1, 1 as id2, 'Alpha' as id3 union all
select null as id1, 2 as id2, 'Beta' as id3 union all
select 'A' as id1, 2 as id2, null as id3
)s
)s --pass1
;
OK
id1 id2 id3 groupid2
A 1 NULL A
NULL 1 Alpha A
A 2 NULL A
NULL 2 Beta A
Time taken: 106.944 seconds, Fetched: 4 row(s)