Litecoin Bitcoin how divide uint256 target value on difficulty in C

Question

I get unit256 class from litecoin wallet source, but this class dont have divide operator. So i convert uint256 to double which have implemintation in uint256 class

double getdouble() const
{
   double ret = 0.0;
   double fact = 1.0;
   for (int i = 0; i < WIDTH; i++) {
       ret += fact * pn[i];
       fact *= 4294967296.0;
   }
   return ret;
}

But now i need convert this huge double to hex string. This string will be represent target for miner, as far i understand. Or i need this double variable converts back to uint256 and thet get hex from it. 

Answer 1

This is the solution:

void setdouble(double val)
{
    double ret = val;
    double fact = 1.0;
    for (int i = 0; i < WIDTH; i++) {
        double a = ret / fact;
        pn[i] =  (uint32_t)a;
        fact *= 4294967296.0;
    }
}