Difference between struct and typedef struct in C

In C++, is there any difference between:

struct Foo { ... };

and:

typedef struct { ... } Foo;

Aug 8, 2022 in C++ by Nicholas
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What is the difference between public, private, and protected inheritance in C++?

To begin answering that question, let me characterise member accessors in my own terms. If you already know this, proceed to the section "next:". I'm aware of three types of accessors: public, protected, and private. Let: class Base { public: ...READ MORE

answered Jul 11, 2022 in C++ by Damon
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Jul 11, 2022 in C++ by Nicholas
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Some people use the latter word to ...READ MORE

answered Aug 2, 2022 in C++ by Damon
• 4,960 points • 1,927 views

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What distinguishes std::list<std::pair> from std::map? Does the ...READ MORE

Aug 17, 2022 in C++ by Nicholas
• 7,760 points • 616 views

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answered Jun 21, 2022 in C++ by Damon
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answered Jun 21, 2022 in C++ by Damon
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Explanation of function pointers

It's a little perplexing. Function type and pointer to function type are distinct kinds (no more similar than int and pointer to int). However, in virtually all cases, a function type decays to a reference to a function type. In this context, rotting roughly refers to conversion (there is a difference between type conversion and decaying, but you are probably not interested in it right now). What matters is that practically every time you use a function type, you end up with a reference to the function type. But take note of the nearly - almost every time is not always! And there are rare circumstances where it does not. typedef void(functionPtr)(int); functionPtr fun = function; This code tries to clone one function to another (not the pointer! the function!) However, this is not feasible since functions in C++ cannot be copied. The compiler does not let this, and I'm surprised you got it compiled (you say you got linker errors?) Now for the code: typedef void(functionPtr)(int); functionPtr function; function(5); function does ...READ MORE