190236/do-you-use-qt-and-why-do-you-use-it
In C++, I developed a simple application that requested the user to enter a number and then a string. Surprisingly, when I ran the application, it never paused to ask for the string. It simply ignored it. After conducting some research on StackOverflow, I discovered that I needed to include the following line: cin.ignore(256, '\n'); before the line with the string input That addressed the problem and allowed the software to run. My issue is why C++ need the cin.ignore() line, and how can I forecast when I will need to use it. Here's the software I created: #include <iostream> #include <string> using namespace std; int main() { ...READ MORE
"Compile time polymorphism" used to signify function overloading. It only applies to functions because that's all you can overload. Templates in modern C++ modify this. One example has previously been provided by Neil Butterworth. Another technique is template specialisation. As an example: #include <iostream> #include <string> template <class T> struct my_template { ...READ MORE
I've never used it, but I'm curious ...READ MORE
Tokenization is essential in determining what a programme does. What Bjarne is referring to in respect to C++ code is how tokenization rules alter the meaning of a programme. We need to know what the tokens are and how they are determined. Specifically, how can we recognise a single token when it comes among other characters, and how should tokens be delimited if there is ambiguity? Consider the prefix operators ++ and +, for example. Assume we have just one token + to deal with. What does the following excerpt mean? int i = 1; ++i; Is the above going to apply unary + on i twice with + only? Or will it only increase it once? Naturally, it's vague. We require an additional token, thus ++ is introduced as its own "word" in the language. But there is now another (though minor) issue. What if the programmer just wants to use unary + twice without incrementing? Rules for token processing are required. So, if we discover that a white space is always used as a token separator, our programmer may write: int i ...READ MORE
If you don't utilise exceptions, by definition, ...READ MORE
I come from a Java background where ...READ MORE
There is a seemingly undocumented feature of setup that ...READ MORE
Hadoop is not designed for records about ...READ MORE
QT does seem to support a compatible ...READ MORE
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