163234/private-ip-address-identifier-in-regular-expression
I'm curious if the following is the best approach to match a string that begins with a private IP address (Perl-style Regex):
(^127\.0\.0\.1)|(^192\.168)|(^10\.)|(^172\.1[6-9])|(^172\.2[0-9])|(^172\.3[0-1])
I'm assuming you want to match these ranges:
127. 0.0.0 – 127.255.255.255 127.0.0.0 /8 10. 0.0.0 – 10.255.255.255 10.0.0.0 /8 172. 16.0.0 – 172. 31.255.255 172.16.0.0 /12 192.168.0.0 – 192.168.255.255 192.168.0.0 /16
i could get 192.168.1.1 match
The IP address of the nodes connected ...READ MORE
1. Open the Command Prompt. a. Click the Start icon, ...READ MORE
I am using below code for an ...READ MORE
class NetworkId{ static String findClass(String str){ int index = ...READ MORE
You can use the 'str_replace_all()' function from ...READ MORE
Blockhashes are always 64 characters in length. You ...READ MORE
Use gsub to match the substring that we want ...READ MORE
No, .replace() does not support regex. Regular expressions ...READ MORE
Is it correct that mobile phones utilise ...READ MORE
ARP may be used to retrieve an ...READ MORE
OR
At least 1 upper-case and 1 lower-case letter
Minimum 8 characters and Maximum 50 characters
Already have an account? Sign in.