How to sort an array in java

Question

I was making an array with 10 elements which consist of random values. Now i want to sort them in order of lowest to highest value. How would I write a code for the same?

Answer 1

int[] arr = new int[10];
Random r = new Random();
for (int i = 0; i < arr.length; i++)
    arr[i] = r.nextInt(100) + 1;
Arrays.sort(arr);
System.out.println(Arrays.toString(arr));
for (int i = arr.length - 1; i >= 0; i--)
    System.out.print(arr[i] + " ");
System.out.println();

Answer 2

public void bubbleSort(int[] array) {
    boolean swapped = true;
    int j = 0;
    int tmp;
    while (swapped) {
        swapped = false;
        j++;
        for (int i = 0; i < array.length - j; i++) {
            if (array[i] > array[i + 1]) {
                tmp = array[i];
                array[i] = array[i + 1];
                array[i + 1] = tmp;
                swapped = true;
            }
        }
    }
}

Answer 3

import java.util.Arrays;


public class Sort {
    public static void main(String args[])
    {
        int [] array = new int[10];
        for ( int i = 0 ; i < array.length ; i++ ) {
            array[i] = ((int)(Math.random()*100+1));
        }
        Arrays.sort( array );
        for ( int i = 0 ; i < array.length ; i++ ) {
            System.out.println(array[i]);
        }
    }
}