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The Java Collection Framework contains numerous interfaces, one of which is the Set Interface. This article will give you a detailed introduction to Sets In Java. Following are the pointers to be covered in this article:
Set be defined as a collection of unordered elements; wherein duplicate values cannot be stored. It extends Collection and thus all methods in the Collection interface are available in the Set interface. It is implemented by HashSet, LinkedHashSet, or the TreeSort.
Each of these implementations act differently while iterating the set, mostly with respect to the ordering of the elements, and the time taken for insertion and for accessing the elements.
The following code defines the method of creating a new set:
Set<Integer> num = new HashSet<>();
We have used generics to declare the set of an integer type.
We can perform multiple operations on a set such as follows:
The add method inserts an element to the Java collection. In the code below, we insert a set of names.
Set<String> strName = new HashSet<>(); strName.add("John"); strName.add("Doe"); System.out.println(strName);
Output:
[John, Doe]
This method removes the specified element from the set.
import java.util.*; public class Main{ public static void main(String args[]) { // Creating an Empty Set Set<String> set = new HashSet<String>(); //Adding elements to the set set.add("John"); set.add("Doe"); // Display the set System.out.println("Set: " + set); // Removing the element “Doe” using remove() method set.remove("Doe"); // Displaying the modified set System.out.println("Set : " + set); } }
Output:
Set : [John, Doe]
Set : [John]
This method checks determines whether the set is empty is not. It returns true if the set is empty, and false if otherwise.
import java.io.*; import java.util.*; public class Main { public static void main(String args[]) { Set<String> javaSet = new HashSet<String>(); // Adding elements to the Set javaSet.add("John"); javaSet.add("Doe"); // Display the set System.out.println("Set: " + javaSet); // Checking whether the set is empty System.out.println("Empty Set : " + javaSet.isEmpty()); // Clearing the set using the clear() method javaSet.clear(); // Checking whether the set is empty System.out.println("Empty Set : " + javaSet.isEmpty()); } }
Output:
Set : [John, Doe]
Empty Set : false
Empty Set : true
The size() method returns the size of the set, i.e. the number of elements present in the set.
import java.util.*; public class Main { public static void main(String args[]) { // Creating a set Set<String> set = new HashSet<String>(); set.add("John"); set.add("Doe"); System.out.println("Set: " + set); // Displaying the size of the sent System.out.println("Size of the set : " + set.size()); } }
Output:
Size of the set : 2
We can iterate over all the elements present in the set by the following method:
import java.util.*; import java.util.HashSet; public class Main { public static void main(String args[]) { // Creating a HashSet HashSet<String> javaSet = new HashSet<String>(); javaSet.add("John"); javaSet.add("Doe"); // Displaying the set System.out.println("HashSet: " + javaSet); // Creating an iterator Iterator itr = javaSet.iterator(); // Displaying the values after iteration System.out.println("Iterator values: "); while (itr.hasNext()) { System.out.println(itr.next()); } } }
Output:
HashSet : [John, Doe]
Iterator Values:
John
Doe
Searching in A Set
We use the contains() method to determine whether the set contains a specified element. Returns true if the element is found and false otherwise.
import java.io.*; import java.util.HashSet; public class Main { public static void main(String args[]) { // Creating a HashSet HashSet<String> javaSet = new HashSet<String>(); javaSet.add("John"); javaSet.add("Doe"); // Displaying the HashSet System.out.println("HashSet: " + javaSet); // Checking for “John” in the set System.out.println("John in set: " + javaSet.contains("John")); // Checking for "Hazel" in set System.out.println("Hazel in set: " + javaSet.contains("Hazel")); } }
Output:
HashSet : [John, Doe]
John in set: true
Hazel in set: false
Example
import java.util.*; public class Main { public static void main(String args[]) { Set<Integer> d = new HashSet<Integer>(); d.addAll(Arrays.asList(new Integer[] {3, 2, 1, 9, 6, 4, 0})); Set<Integer> e = new HashSet<Integer>(); e.addAll(Arrays.asList(new Integer[] {3, 1, 9, 5, 2, 0, 7,})); // Union Operation Set<Integer> union = new HashSet<Integer>(d); union.addAll(e); System.out.println("Union :" + union); // Intersection Operation Set<Integer> intersection = new HashSet<Integer>(d); intersection.retainAll(e); System.out.println("Intersection :" + intersection); // Difference Operation Set<Integer> difference = new HashSet<Integer>(d); difference.removeAll(e); System.out.println("Difference :" + difference); } }
Output:
Union : [0, 1, 2, 3, 4, 5, 6, 7, 9]
Intersection : [0, 1, 2, 3, 9]
Difference : [4, 6]
The methods and the operations mentioned in the method make the set interface elemental and efficient in nature.
Thus we have come to an end of this article on ‘Sets in Java’. If you wish to learn more, check out the Java Training by Edureka, a trusted online learning company. Edureka’s Java J2EE and SOA training and certification course is designed to train you for both core and advanced Java concepts along with various Java frameworks like Hibernate & Spring.
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